A. CONFORMATIONAL ISOMERS

Size: px
Start display at page:

Download "A. CONFORMATIONAL ISOMERS"

Transcription

1 EMISTRY 104 elp Sheet #3 Organic (Part II): ISOMERS hapters 2.9 (structural isomers), 6.5 (geometric isomers), 6.11 (constitutional isomers), 7.2f (optical isomers) Do the topics appropriate for your lecture Prepared by Dr. Tony Jacob (Resource page) Nuggets: Isomers (The instructor will clarify which isomers are covered.) ISOMERS Molecules with the same formula but different connectivities or different arrangements in space; (molecules that have different formulas, e.g., 6 12 and 6 14, are not isomers) I. STRUTURAL ISOMERS (also called onstitutional Isomers): same formula, different bonding/connectivities; e.g., 2 different structural isomers of 4 10 : butane = and 2-methylpropane = II. STEREOISOMERS: same formula, same bonding/connectivities but different spatial arrangements (positions) of the atoms A. ONORMATIONAL ISOMERS: isomers differ because of a rotation through a σ-bond; e.g., versus versions of butane shown as a Newman Projection (as done in lab) and dash-wedge: Newman Projections can also be drawn: Dash-Wedge Diagrams B. GEOMETRI ISOMERS ALKENES: cis versus trans configuration Does the molecule have geometric isomers? riteria: 1. Does it contain a = (or a double bond between other atoms) 2. On each of the =, there must be 2 different groups (one of these groups maybe a pair e - ). Both criteria must be true for a molecule to have cis/trans isomers. The molecule below does not have cis/trans isomers no cis or trans {Above molecule does have a double bond and meets the first criteria. The left atom of the = bond does have 2 different groups (it has a 3 and a 2 3 group) but the right atom of the = has two atoms (same group; needs different groups on each of the =).}

2 GEOMETRI ISOMERS (continued): cis versus trans configuration If molecule has geometric isomers, is it cis or trans? Molecule below has a double bond (satisfies the first criteria) and each of the = has two different groups (each has a and a 3 group; satisfies the second criteria) 1. Draw a line through = bond 2. ind the 2 groups that are the same on the 2 of the = and circle them; if they re on the same side of the line cis isomer; different sides trans isomer trans cis GEOMETRI ISOMERS YLI STRUTURES (as discussed in lab) Does the molecule have geometric isomers? riteria: 1. Is the molecule a ring in which atoms can move to cis or trans positions compared to the plane of the ring? cis trans. ENANTIOMER ISOMERS Enantiomers are chiral (pronounced ki-ral) molecules (i.e., they have a chiral center). riteria: To be a chiral center, the atom, usually must have 4 different groups attached to it. (Note: there are exceptions to this usually not covered in hem 104.) If a single atom has 4 different groups attached, the molecule will be chiral have a non-superimposable mirror image the two mirror images are called enantiomer pairs (pronounced ee-nan-tee-oh-mer) The enantiomers (mirror image molecules) will be optically active (interacts with plane-polarized light) have the same physical properties (boiling point, D, etc.) rotate plane-polarized light in different directions (clockwise and counterclockwise), and may differ in their chemical reactivity You must check every atom in the molecule; if any atom has 4 different groups the molecule is chiral. mirror * hiral (denoted with an asterisk, *) has: (not shown), 3, 2 3, and ( 3 ) 2 attached (4 different groups) enantiomers - mirror images not a chiral molecule chiral molecule

3 Summary hemicals (same chemical formula?) No Not Isomers Yes Isomers When comparing two molecules, do they have the same bonding/connectivity? 4 10 = butane 4 10 = 2-methylpropane No Structural Isomers (also called constitutional isomers) Yes Stereoisomers onformational Isomers (e.g., and conformations) Newman Projections Stereoisomers Geometric Isomers (contains a double bond or a ring; cis/trans) cis trans Enantiomers (nearly always contains a with 4 different groups attached; nonsuperimposible mirror images) 3 O O cis trans Dash-Wedge Diagrams A methodology to draw all isomers of a given molecular formula is on the last two pages of this elp Sheet. 1. Draw and name all 3 structural isomers for Use line notation. (Naming the isomers helps to prevent drawing duplicate structures.) 2. Draw and name all 8 structural isomers for Use line notation. (Naming the isomers helps to prevent drawing duplicate structures.) 3. Draw and name all 5 structural isomers for 3 6. Use line notation. (Naming the isomers helps to prevent drawing duplicate structures.) 4. Draw and name all 6 structural and geometric alkene isomers (cis/trans) with the formula 5 10 ; do not include cycloalkanes. (Naming the isomers helps to prevent drawing duplicate structures.)

4 5. Which molecule is chiral? Select answer e if none are chiral. a. O b. c. O d. e. none are chiral 6. Identify which of the following molecules have optical isomers; there may be more than one molecule. O O a. I b c d e Which molecule is a structural isomer of trans-2-butene? a. b. c. d. e. 8. Draw and name all 8 alcohol isomers that can be derived from 5 11 O. (Naming the isomers helps to prevent drawing duplicate structures.) ANSWERS 1. pentane; 2-methylbutane; 2,2-dimethylpropane 2. 1-chloropentane; 2-chloropentane; 3-chloropentane ; 1-chloro-2-methylbutane; 1-chloro-3-methylbutane; 2-chloro-2-methylbutane; 2-chloro-3-methylbutane; 1-chloro-2,2-dimethylpropane 3. 1-bromo-1-chloropropane; 1-bromo-2-chloropropane; 1-bromo-3-chloropropane; 2-bromo-1-chloropropane; 2-bromo-2-chloropropane

5 4. 1-pentene; cis-2-pentene; trans-2-pentene; 2-methyl-1-butene; 3-methyl-1-butene; 2-methyl-2-butene * 5. c {need to find a atom with 4 different groups attached to it; the chiral is denoted with an * 6. a, d, and e have optical isomers O 7. b {trans-2-butene has this structure: and a formula: 4 8 ; a has a formula = 4 10 isomers must have the same formula; b has the same formula and a different structure; c is the cis version of trans-2-butene so it is a geometric isomer not a structural isomer; d has a formula = 5 10 isomers must have the same formula; e has a formula = 5 8 isomers must have the same formula} 8. O O 1-pentanol 2-pentanol O 3-pentanol O O 2-methyl-1-butanol O 3-methyl-1-butanol O 2-methyl-2-butanol 3-methyl-2-butanol O 2,2-dimethyl-1-propanol

6 Ex: Draw all structural isomers with the formula ow to systematically draw structural isomers 1. Determine whether the molecule is an alkane, alkene, etc. Since occupies one site on a atom, it is similar to a atom. ence, the formula, 5 11 is analogous to 5 12 which corresponds to a n 2n+2 formula alkane so 5 11 is also an alkane. 2. Start with the longest chain; in this example, a 5- chain: 3. Place the atom at the far left end of the chain: and name the molecule: 1-chloropentane. 4. Take the for a walk down the chain naming each new molecule: 2-chloropentane 3-chloropentane named incorrectly: 4-chloropentane appears to be a new isomer duplicate; correctly named: 2-chloropentane named incorrectly: 5-chloropentane appears to be a new isomer duplicate; correctly named: 1-chloropentane 5. Once you have identified all 5- chain molecules reduce the chain to a 4- chain. 6. There are now 2 groups to work with: a and a 3 group. The 3 group cannot be placed on either end of the chain otherwise the chain becomes a 5- chain again which is already done. The should be placed on the far left end of the chain. name the molecule: 1-chloro-2-methylbutane 7. Take the for a walk down the 4- chain naming each new molecule: 2-chloro-2-methylbutane 2-chloro-3-methylbutane 1-chloro-3-methylbutane 8. Move the 3 group to the next position on the chain; this position is still in position 2 (reading right to left) so all the next molecules will be duplicates. ence, all 4- chain isomers have been identified and now reduce the chain to a 3- chain. 9. Note: There are now 3 groups to work on: a and two 3 groups. The 3 groups cannot be placed on either end of the chain otherwise the chain becomes a 4- chain again which is already done so they must go on the middle ; the is placed on the far left end of the chain. name the molecule: 1-chloro-2,2-dimethylpropane 10. Take the for a walk down the 3- chain naming each new molecule: 2-chloro-2,2-dimethylpropane Note: this molecule is NOT allowed since the middle atom has 5 bonds! named incorrectly: 3-chloro-2,2-dimethylpropane appears to be a new isomer duplicate; correctly named: 1-chloro-2,2-dimethylpropane 11. inally check to see if the 2 3 groups can be combined into a 2- ethyl group and start the at the far left end of the chain: 5- chains: 4- chains: 3- chains: named incorrectly: 1-chloro-2-ethylpropane appears to be a new isomer duplicate; correctly named: 1-chloro-2-methylbutane 1-chloropentane 2-chloropentane 3-chloropentane 1-chloro-2-methylbutane 2-chloro-2-methylbutane 2-chloro-3-methylbutane 1-chloro-3-methylbutane 1-chloro-2,2-dimethylpropane

7 ow to systematically draw structural AND geometric isomers Ex: Draw all structural and geometric isomers with the formula 4 7 ; don t include cyclic compounds. 1. Determine whether the molecule is an alkane, alkene, etc. Since occupies one site on a atom, it is similar to a atom. ence, the formula, 4 7 is analogous to 4 8 which corresponds to a n 2n formula alkene so 4 7 is also an alkene. 2. Start with the longest chain; in this example, a 4- chain: 3. Place the atom and the double bond at the far left end of the chain: and name the molecule: 1-chloro-1-butene. 4. heck for cis/trans isomers; this molecule has cis/trans isomers; draw the other isomer by flipping one pair of atoms on one of the = double; rename as trans-1-chloro-1-butene 5. name the molecule: cis-1-chloro-1-butene 6. Take the for a walk down the chain naming each new molecule and checking for cis/trans isomers: 2-chloro-1-butene (no cis/trans isomers) 3-chloro-1-butene (no cis/trans isomers) 4-chloro-1-butene (no cis/trans isomers) 7. ing the back to the far left side of the chain and move the double bond. Take the for a walk down the chain naming each new molecule and checking for cis/trans isomers: 1-chloro-2-butene; has cis/trans: rename as trans-1-chloro-2-butene cis-1-chloro-2-butene 2-chloro-2-butene; has cis/trans: rename as trans-2-chloro-2-butene cis-2-chloro-2-butene named incorrectly: 3-chloro-2-butene appears to be a new isomer duplicate; correctly named: trans-2-chloro-2-butene named incorrectly: 4-chloro-2-butene appears to be a new isomer duplicate; correctly named: trans-1-chloro-2-butene 8. Once you have identified all 4- chain molecules reduce the chain to a 3- chain. 9. There are 3 groups to work with:, 3 group, and a double bond. The 3 group cannot be placed on either end of the chain otherwise it becomes a 4- chain and must be placed on position 2; the is placed on the far left end of the chain; the double bond is placed in position 1. name the molecule: 1-chloro-2-methyl-1-propene (no cis/trans isomers) 10. Take the for a walk down the 3- chain naming each new molecule: 2-chloro-2-methyl-1-propene Note: this molecule is NOT allowed since the middle atom has 5 bonds! 3-chloro-2-methyl-1-propene (no cis/trans isomers) 11. Move the double bond to the next position and bring the back to the far left position: named incorrectly: 1-chloro-2-methyl-2-propene appears to be a new isomer duplicate; correctly named: 3-chloro-2-methyl-1- propene 12. The next two positions will yield duplicate isomers. The 3 cannot be moved from the second position without increasing the chain length, and a 2- chain is not possible. Done! 4- chains: trans-1-chloro-1-butene cis-1-chloro-1-butene 2-chloro-1-butene 3-chloro-1-butene 4-chloro-1-butene trans-1-chloro-2-butene cis-1-chloro-2-butene trans-2-chloro-2-butene cis-2-chloro-2-butene 3- chains: 1-chloro-2-methyl-1-propene 3-chloro-2-methyl-1-propene

CHEM 109A Organic Chemistry

CHEM 109A Organic Chemistry CEM 09A Organic Chemistry https://labs.chem.ucsb.edu/zakarian/armen/courses.html Chapter Isomers The arrangement of atoms in space MIDTERM Wednesday Feb. Chapter Sections.8.6 melting, boiling points, conformations

More information

Practice Problems for Video CH 5-1:

Practice Problems for Video CH 5-1: CEM 243 Organic Chemistry C-5: Stereochemistry - Chiral Molecules Study Guide: Key Concepts and Practice Problems Key concepts you need to understand: Chirality and chiral centers; stereoisomers; (R,S)

More information

CHAPTER 5 HW: STEREOISOMERS

CHAPTER 5 HW: STEREOISOMERS CAPTER 5 W: STEREISMERS CIRALITY AND ENANTIMERS 1. Define the following terms: a. Chiral A chiral substance has the possibility of having right and left handed versions (or it can have an enantiomer).

More information

CHM 220 Stereochemistry

CHM 220 Stereochemistry CM 220 Stereochemistry Stereocenters 1. ow many stereocenters are there in 2,2,4-tribromo-3-methyl-1-pentanol? (A) 2 (B) 3 (C) 4 (D) 5 2. ow many stereocenters are there in 2,3-dibromo-4-methylpentane?

More information

ANSWERS: Isomers. 2) A and F

ANSWERS: Isomers. 2) A and F NSWERS: Isomers 1) For cis and trans isomers to occur a carbon-carbon double bond must be present as this prevents any rotation about this bond, and the atoms or groups of atoms attached to the two carbon

More information

CHAPTER 5 HW: STEREOISOMERS

CHAPTER 5 HW: STEREOISOMERS CAPTER 5 W: STEREISMERS CIRALITY AND ENANTIMERS 1. Define the following terms: a. Chiral b. Enantiomers (and give an example) 2. Put an asterisk (*) on all chiral centers in these compounds. Some may have

More information

Teacher s Tools Chemistry Organic Chemistry: Nomenclature and Isomerism

Teacher s Tools Chemistry Organic Chemistry: Nomenclature and Isomerism 1. Hydrocarbons: a) Naming of hydrocarbons is done based on the number of carbons. 1 = meth 6 = hex 2 = eth 7 = hept 3 = prop 8 = oct 4 = but 9 = non 5 = pent 10 = dec b) Alkanes are hydrocarbons without

More information

Oregon State University

Oregon State University H 223 Worksheet 9 Notes Oregon State University 1. Draw a primary alcohol and name it. OH 1-propanol Note: A primary alcohol has the form RH 2 OH; a secondary alcohol has the form R 2 H OH; and a tertiary

More information

CHAPTER 26 STEREOISOMERISM SOLUTIONS TO REVIEW QUESTIONS

CHAPTER 26 STEREOISOMERISM SOLUTIONS TO REVIEW QUESTIONS C26 09/17/2013 10:52:31 Page 379 CHAPTER 26 STEREOISOMERISM SOLUTIONS TO REVIEW QUESTIONS 1. A chiral carbon atom is one to which four different atoms or groups are attached and is a center of asymmetry

More information

Chirality. Chapter 5 Stereochemistry. Chiral Carbons. Stereoisomers. Mirror Planes of Symmetry. (R), (S) Nomenclature

Chirality. Chapter 5 Stereochemistry. Chiral Carbons. Stereoisomers. Mirror Planes of Symmetry. (R), (S) Nomenclature Organic hemistry, 5 th Edition L. G. Wade, Jr. hapter 5 Stereochemistry hirality andedness : right glove doesn t fit the left hand. Mirror-image object is different from the original object. Jo Blackburn

More information

Stereochemistry 1.1 INTRODUCTION

Stereochemistry 1.1 INTRODUCTION 1 Stereochemistry 1.1 INTRODUTION The isomers which have same arrangement of atoms but differ only due to different orientation of atoms in space within the molecule are called Stereoisomers and the phenomenon

More information

UNSATURATED HYDROCARBONS

UNSATURATED HYDROCARBONS hemistry 52 hapter 20 UNSATURATED YDROARBONS The unsaturated hydrocarbons consist of three families of homologous compounds that contain multiple bonds between carbon atoms. Alkenes contain carbon carbon

More information

Stereochemistry. Dr. Sapna Gupta

Stereochemistry. Dr. Sapna Gupta Stereochemistry Dr. Sapna Gupta Introduction Stereo left and right handedness Any carbon that has four different groups will show chirality. hirality: the mirror image of the compound will not superimpose

More information

Level 3 Chemistry, 2007

Level 3 Chemistry, 2007 Level 3 hemistry, 2007 Annotated answers to this organic paper. Q1 QUESTIN NE Give the proper name that gives the structure a unique name (a) Give the systematic IUPA names for the following molecules

More information

As a result, IV and V are chiral molecules and are enantiomers.

As a result, IV and V are chiral molecules and are enantiomers. 5.1 lassify each of the following objects as to whether it is chiral or achiral: (a) A screwdriver achiral (d) A tennis shoe chiral (g) A car chiral (b) A baseball bat achiral (e) An ear chiral (h) A hammer

More information

Alkenes and Alkynes: Structure and Nomenclature

Alkenes and Alkynes: Structure and Nomenclature hapter 3 3 : Structure and Nomenclature APTER SUMMARY 3.1 Introduction to Alkenes are hydrocarbons in which there is at least one carbon-carbon double bond; alkynes have at least one carbon-carbon triple

More information

Organic. Carbon Chemistry

Organic. Carbon Chemistry Today Organic Carbon Chemistry Organic You know more than you think already What you will need Lewis dot, VSEPR VB, hybrid orbitals, MO electronegativity intermolecular forces Two hurdles we will deal

More information

1. Draw a standard line bond structure for compounds of the following molecular formulas:

1. Draw a standard line bond structure for compounds of the following molecular formulas: TF ame: LS1a Fall 06 Problem Set #1 Due Friday 9/29 at noon in your TF s drop box on the 2 nd floor of Science Center all questions including extra ones should be turned in 1. Draw a standard line bond

More information

Stereochemistry: 3-D Chemistry. 3-D Chemistry. Enantiomers

Stereochemistry: 3-D Chemistry. 3-D Chemistry. Enantiomers Stereochemistry: 3-D Chemistry 3-D Chemistry Enantiomers If a molecule and its mirror image are not superimposable these molecules are isomers; in particular, these mirror image isomers are called enantiomers

More information

1. Butane. 2. trans-2-methylcyclohexanol. 3. 1,2-dimethylcyclohexene. Chem 131 Spring 2018 Exam I Practice

1. Butane. 2. trans-2-methylcyclohexanol. 3. 1,2-dimethylcyclohexene. Chem 131 Spring 2018 Exam I Practice Chem 131 Spring 2018 Exam I Practice Thursday s examination will contain 31 questions valued at 3.5 points/question, with some bonus possibilities available Name KEY Name the following compounds. 1. Butane

More information

Chemistry 261 Homework 3: Chapters 5, 6 Out: 11/20/17 Due: 11/30/17 Point Value: 9 points (7 EC points possible when combined with part I)

Chemistry 261 Homework 3: Chapters 5, 6 Out: 11/20/17 Due: 11/30/17 Point Value: 9 points (7 EC points possible when combined with part I) Chemistry 261 omework 3: Chapters 5, 6 ut: 11/20/17 Due: 11/30/17 Point Value: 9 points (7 EC points possible when combined with part I) The following homework assignment contains 28 questions valued at

More information

Carbohydrates. Chapter 18

Carbohydrates. Chapter 18 Carbohydrates Chapter 18 Biochemistry an overview Biochemistry is the study of chemical substances in living organisms and the chemical interactions of these substances with each other. Biochemical substances

More information

CH 3 H C 2 H 5. C Cl C H. H 3 C Cl H H 5 C 2. H Cl. Cl H. C Cl H. H Cl. Problem Set 7: Stereochemistry-2

CH 3 H C 2 H 5. C Cl C H. H 3 C Cl H H 5 C 2. H Cl. Cl H. C Cl H. H Cl. Problem Set 7: Stereochemistry-2 Problem Set 7: Stereochemistry-2 hemistry 260 Organic hemistry 1. ow many constitutional isomers of 7 16 have stereogenic centres? (1) 1 (2) 2 (3) 3 (4) 4 (5) none 2. Indicate which of the following compounds

More information

Chem 105X Friday, Dec. 2, Chapter 10, Kotz Organic Chemistry

Chem 105X Friday, Dec. 2, Chapter 10, Kotz Organic Chemistry our Exam 4 (Chap 9, 10, 11) will be given in this room Friday, Dec. 9. A practice exam is posted on the course website. Review for the exam will occur Wednesday, Dec. 7 in class. Chem 105X Friday, Dec.

More information

6.1 Cis Trans Isomers

6.1 Cis Trans Isomers 6.1 CIS TRANS ISMERS 179 two dimensions on the pages of a book. The use of models is an invaluable aid in understanding the material presented in this chapter. You are strongly encouraged to build models

More information

Problem Set 2 Out: November 5, 1999 Due Back: November 12, 1999 Chemistry 221, 1999

Problem Set 2 Out: November 5, 1999 Due Back: November 12, 1999 Chemistry 221, 1999 Problem Set ut: November 5, 1999 Due Back: November 1, 1999 hemistry 1, 1999 Answers to the following problems should be written, in order and labeled, on 8 1/ x 11 inch paper. Answers written on the problem

More information

3.7A: Compounds with multiple stereocenters

3.7A: Compounds with multiple stereocenters Ashley Robison My Preferences Site Tools FAQ Sign Out If you like us, please share us on social media. The latest UCD Hyperlibrary newsletter is now complete, check it out. ChemWiki BioWiki GeoWiki StatWiki

More information

Fuels. 1. Combustion is an example of an exothermic reaction which will give out energy, endothermic reactions are the opposite

Fuels. 1. Combustion is an example of an exothermic reaction which will give out energy, endothermic reactions are the opposite Fuels 1. ombustion is an example of an exothermic reaction which will give out energy, endothermic reactions are the opposite overed ( ) ow well can you do this? 2. The energy given out by a fuel can be

More information

CHEM 203 HOMEWORK 4 Chemistry of Alkenes - II. Answer the above questions by writing a detailed mechanism for the conversion of A into lanosterol.

CHEM 203 HOMEWORK 4 Chemistry of Alkenes - II. Answer the above questions by writing a detailed mechanism for the conversion of A into lanosterol. EM 203 MEWK 4 hemistry of Alkenes - II 1. The following questions may have occurred to you: (i) do carbocations occur in living systems? (ii) an an olefin (a Lewis base) react with a carbocation (a Lewis

More information

TEST-7/11 th, 12 th & 12 th Passed /Set-P

TEST-7/11 th, 12 th & 12 th Passed /Set-P III-A/172, Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091. email : bmcchemistry@gmail.com, website : www.bmcchemistry.com Type : JEE MAIN 2015-16 TEST-7/11 th, 12 th & 12 th Passed /Set-P Topic : rganic

More information

Alkane C-C single bond (propane) Alkene C=C double bond (propene) Alcohol - OH group (1-propanol) major. minor

Alkane C-C single bond (propane) Alkene C=C double bond (propene) Alcohol - OH group (1-propanol) major. minor Functional group* and name? Alkane - single bond (propane) *alkanes not really regarded as a functional group Alkene = double bond (propene) Addition of an unsymmetrical reagent to unsymmetrical alkene

More information

S4 Chemistry National 5

S4 Chemistry National 5 S4 hemistry National 5 Nature s hemistry Unit ourse Notes- ydrocarbons and onsumer Products Name lass 1 ydrocarbons ydrocarbons can be categorised into family groups known as OMOLOGOUS SERIES. A homologous

More information

Please read and sign the Honor Code statement below:

Please read and sign the Honor Code statement below: CHEM 3311 Exam #1 Name Dr. Minger June 6, 2016 Please read and sign the Honor Code statement below: I pledge that on my honor, as a University of Colorado at Boulder student, I have neither given nor received

More information

Stereochemistry - Chirality. Chapter 5 Organic Chemistry, 8th Edition John E. McMurry

Stereochemistry - Chirality. Chapter 5 Organic Chemistry, 8th Edition John E. McMurry Stereochemistry - Chirality Chapter 5 Organic Chemistry, 8th Edition John E. McMurry Isomerism The two major classes of isomers are constitutional isomers and stereoisomers. Constitutional/structural isomers

More information

CHE 102 Exam 3 CH 3 CHCOOH. CH 3 CH 2 CH 2 O d. e. f. CH3 COO g. h. i. O O CH 3 CCH 2 CCH 3

CHE 102 Exam 3 CH 3 CHCOOH. CH 3 CH 2 CH 2 O d. e. f. CH3 COO g. h. i. O O CH 3 CCH 2 CCH 3 CE 102 Exam 3 1. (1 pt each) Classify the following molecules as aldehydes, ketones, carboxylic acids, or esters: a. b. c. C C 3 CC C 2 C 2 CC 3 C 3 C 2 C 2 d. e. f. CCC 3 C 3 C 3 CC 2 C 2 C C3 C g. h.

More information

Organic Chemistry. Carey/Giuliano 10th edition. Chapter 10

Organic Chemistry. Carey/Giuliano 10th edition. Chapter 10 Organic Chemistry Carey/Giuliano 10th edition Chapter 10 Copyright 2017 McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior written consent of McGraw-Hill Education.

More information

Chem 1120 Final 210 points Dr. Luther Giddings

Chem 1120 Final 210 points Dr. Luther Giddings Chem 1120 Final 210 points Dr. Luther Giddings Name Phone or E-Mail Instructions: This is a closed book, closed notebook test. You may not discuss this exam with anyone, either during or after the exam,

More information

Chapter 5 Stereochemistry

Chapter 5 Stereochemistry Organic Chemistry, Fifth Edition Janice Gorzynski Smith Modified by Dr. Juliet Hahn Chapter 5 Stereochemistry 1 Stereoisomers of 2,3-dibromobutane Figure 5.9 Pair of enantiomers: A and B Pairs of diastereomers:

More information

DEPARTMENT OF MEDICINAL CHEMISTRY SCHOOL OF PHARMACY

DEPARTMENT OF MEDICINAL CHEMISTRY SCHOOL OF PHARMACY KEY DEPARTMET F MEDIIAL EMISTRY SL F PARMAY BASI PARMAEUTIAL SIEE FR TE PRATIIG PARMAIST MED 527, Fall 2008 Quiz #4, Dr. Desai, 100 points; ovember 4, 2008 AME (In APITAL Letters LY) I affirm that I have

More information

Chemistry I (Organic) Stereochemistry LECTURE 2 Stereogenic elements & enantiomers

Chemistry I (Organic) Stereochemistry LECTURE 2 Stereogenic elements & enantiomers 1 Chemistry I (Organic) Stereochemistry LECTURE 2 Stereogenic elements & enantiomers Alan C. Spivey a.c.spivey@imperial.ac.uk Oct 2011 2 Format & scope of lecture Isomers & stereoisomers some definitions

More information

Alkanes. 1. Predict the molecular formula of an alkane with 13 carbon atoms The table below lists the boiling points of some alkanes.

Alkanes. 1. Predict the molecular formula of an alkane with 13 carbon atoms The table below lists the boiling points of some alkanes. Alkanes 1. Predict the molecular formula of an alkane with 13 carbon atoms.... [Total 1 mark]. The table below lists the boiling points of some alkanes. alkane number of carbon atoms molecular formula

More information

Alkenes. Isomerism in the alkenes

Alkenes. Isomerism in the alkenes Alkenes Alkenes are a family of hydrocarbons (compounds containing carbon and hydrogen only) containing a carbon-carbon double bond. The first two are: ethene 2 4 propene 3 6 You can work out the formula

More information

Chapter 12 Alkenes & Alkynes. Organic and BioChem

Chapter 12 Alkenes & Alkynes. Organic and BioChem hapter 12 Alkenes & Alkynes Organic and Biohem Section 12.1 Introduction Unsaturated ydrocarbons ontain one or more carbon-carbon double or triple bonds 3 6? 2 2? Three lasses of Unsaturated ydrocarbons

More information

Stereochemistry: biological significance of isomerism

Stereochemistry: biological significance of isomerism S Stereochemistry: biological significance of isomerism Craig Wheelock October 17 th, 2008 craig.wheelock@ki.se http://www.metabolomics.se/ (copies of slides can be downloaded from my homepage) Learning

More information

Unsaturated Hydrocarbons

Unsaturated Hydrocarbons Interchapter G Unsaturated ydrocarbons FPO aption TK. G. unsaturated ydrocarbons G1 In this Interchapter, we shall continue our introduction to organic chemistry by discussing unsaturated hydrocarbons.

More information

Chapter 3 Structure and Stereochemistry of Alkanes. Classification Review. Alkenes: Structure and Stereochem Slide 3-2

Chapter 3 Structure and Stereochemistry of Alkanes. Classification Review. Alkenes: Structure and Stereochem Slide 3-2 hapter 3 Structure and Stereochemistry of Alkanes lassification Review Alkenes: Structure and Stereochem Slide 3-2 1 Alkane Structural Formulas All - single bonds Saturated with hydrogens (no pi bonds)

More information

CHEM 261 Feb. 16, stereogenic center H C C C

CHEM 261 Feb. 16, stereogenic center H C C C 77 EM 261 Feb. 16, 2017 eview of hiral enters 3 quinine - anti-malarial drug from the bark of the tree inchona officinalis malaria is cause by Plasmodium species transmitted by Anopheles mosquito example.

More information

Org/Biochem Final Lec Form, Spring 2012 Page 1 of 6

Org/Biochem Final Lec Form, Spring 2012 Page 1 of 6 Page 1 of 6 Missing Complete Protein and Question #45 Key Terms: Fill in the blank in the following 25 statements with one of the key terms in the table. Each key term may only be used once. Print legibly.

More information

Chapter 9 Lecture Notes: Carboxylic Acids, Amines, and Amides

Chapter 9 Lecture Notes: Carboxylic Acids, Amines, and Amides Educational Goals Chapter 9 Lecture Notes: Carboxylic Acids, Amines, and Amides 1. Given the structure of a carboxylic acid, carboxylate ion, ester, amide, or amine molecule, be able to give the systematic

More information

Organic Chemistry. Chapter 23. Hill, Petrucci, McCreary & Perry 4 th. Ed. Alkane to Substituent Group methane CH 4 methyl CH 3

Organic Chemistry. Chapter 23. Hill, Petrucci, McCreary & Perry 4 th. Ed. Alkane to Substituent Group methane CH 4 methyl CH 3 hapter 23 rganic hemistry ill, Petrucci, Mcreary & Perry 4 th Ed. Alkane to Substituent Group methane 4 methyl 3 ethane 3 3 ethyl 3 2 propane 3 2 3 propyl 3 2 2 isopropyl ( 3 ) 2 or 3 3 butyl 3 2 2 2 butane

More information

Chapter 9 Educational Goals

Chapter 9 Educational Goals Chapter 9 Educational Goals 1. Given the structure of a carboxylic acid, carboxylate ion, ester, amide, or amine molecule, be able to give the systematic names and vice versa. 2. Know and understand the

More information

Chapter 13: Alcohols, Phenols, and Ethers

Chapter 13: Alcohols, Phenols, and Ethers Chapter 13: Alcohols, Phenols, and Ethers ALCOHOLS, PHENOLS, AND ETHERS Hydroxy group the OH functional group An alcohol has an OH group attached to an aliphatic carbon. General formula: R-OH A phenol

More information

Chapter 4 - Carbon Compounds

Chapter 4 - Carbon Compounds Chapter 4 - Carbon Compounds Carbon compounds organic compounds are tied up with living organisms. So much so, that as we have seen, the presence of methane might be considered an indicator of life. Methane

More information

Organic/Biochem Test #2 Takehome Name: Spring 2012 Page 1 of 6. Multiple choice: Circle the best answer for each of the following questions.

Organic/Biochem Test #2 Takehome Name: Spring 2012 Page 1 of 6. Multiple choice: Circle the best answer for each of the following questions. Spring 2012 Page 1 of 6 Multiple choice: Circle the best answer for each of the following questions. 1. The general formula for a carboxylic acid is: a) RCHO b) RCOR c) R-OH d) R-COOH 2. In which of the

More information

4/7/2011. Chapter 13 Organic Chemistry. Structural Formulas. 3. Petroleum Products

4/7/2011. Chapter 13 Organic Chemistry. Structural Formulas. 3. Petroleum Products Chapter 13 Organic Chemistry 13-1. Carbon Bonds 13-2. Alkanes 13-3. Petroleum Products 13-5. Isomers 13-6. Unsaturated Hydrocarbons 13-7. Benzene 13-9. 13-10. Polymers 13-11. Carbohydrates 13-12. Photosynthesis

More information

Chapter 24. The Chemistry of Life: Organic and Biological Chemistry. Lecture Presentation. James F. Kirby Quinnipiac University Hamden, CT

Chapter 24. The Chemistry of Life: Organic and Biological Chemistry. Lecture Presentation. James F. Kirby Quinnipiac University Hamden, CT Lecture Presentation Chapter 24 The of Life: James F. Kirby Quinnipiac University Hamden, CT Organic and Biochemistry Chapter focus: the molecules that bridge chemistry & biology Most common elements:

More information

CHEM J-6 June 2014

CHEM J-6 June 2014 CEM1611 2014-J-6 June 2014 rlistat (shown below) is a drug for obesity management which acts by inhibiting the absorption of dietary fats. Indicate all stereogenic centres on the structure below. 6 rlistat

More information

Carbohydrate Structure and Nomenclature. Essentials of Glycobiology 1 April 2004

Carbohydrate Structure and Nomenclature. Essentials of Glycobiology 1 April 2004 1 Carbohydrate Structure and Nomenclature Essentials of Glycobiology 1 April 2004 Nathaniel Finney Dept. of Chemistry and Biochemistry UCSD nfinney@chem.ucsd.edu 2 Lecture utline 1. Carbohydrates - definition

More information

1 C 2 C 3 C 4 C 5 C 6 C 7 C 8 C

1 C 2 C 3 C 4 C 5 C 6 C 7 C 8 C I. Carbon atoms form an enormous variety of structures A. Carbon has 4 valence electrons in the outer shell and therefore may form up to 4 covalent bonds B. Carbon tends to bond to C, H, O, N, S, and P

More information

Topic 6 : Structures and Reactions of Hydrocarbons Revised April Alkanes (General formula : C x H 2x+2 )

Topic 6 : Structures and Reactions of Hydrocarbons Revised April Alkanes (General formula : C x H 2x+2 ) 6/1 Topic 6 : Structures and Reactions of ydrocarbons Revised April 1995 ydrocarbons all contain arbon and ydrogen only. There are various families of hydrocarbons (subsets of the set of hydrocarbons)

More information

Chapter 05 Structure and Preparation of Alkenes: Elimination Reactions part 01

Chapter 05 Structure and Preparation of Alkenes: Elimination Reactions part 01 hapter 05 Structure and Preparation of Alkenes: Elimination Reactions part 01 EM 341: Spring 2012 Prof. Greg ook 2012 Gregory R ook Alkenes ompounds that contain double bonds. Ethylene (Ethene) 2 2012

More information

PRACTICE PROBLEMS CHEMISTRY

PRACTICE PROBLEMS CHEMISTRY PRATIE PRBLEMS EMISTRY G ame: Batch: Date: 1. Which nitrogen in LSD is most basic: 1 2 3 3 ( 2 5 ) 2 (A) 1 2 () 3 All are equally basic 2. Which of the following statement for 2 = 2, 2 = 3 2 is / are correct.

More information

Anomeric carbon Erythritol is achiral because of a mirror plane in the molecule and therefore, the product is optically inactive.

Anomeric carbon Erythritol is achiral because of a mirror plane in the molecule and therefore, the product is optically inactive. APTER 22 Practice Exercises 22.1 2 2 2 2 2 2 2 2 D-Ribulose L-Ribulose D-Xyulose L-Xyulose (one pair of enantiomers) (a second pair of enantiomers) 22.3 2 Anomeric carbon Glycosidic bond 3 () Methyl -D-mannopyranoside

More information

13. ORGANIC CHEMISTRY

13. ORGANIC CHEMISTRY 1. ORGANIC EMISTRY III) ALKENES SYNOPSIS Alkenes are unsaturated hydrocarbons. These contain a C =C. They contain two hydrogens less than corresponding alkanes. Double bonded carbon undergoes hybridisation.

More information

10/29/ Stability of Alkenes. Stability of Alkenes. Stability of Alkenes

10/29/ Stability of Alkenes. Stability of Alkenes. Stability of Alkenes 7.5 Stability of cis and trans isomers Interconversion does not occur spontaneously Cis isomers are less stable than trans isomers because of the steric strain between the two larger substituents on the

More information

Fundamentals of Organic Chemistry. CHAPTER 6: Carbohydrates

Fundamentals of Organic Chemistry. CHAPTER 6: Carbohydrates Fundamentals of Organic Chemistry CHEM 109 For Students of Health Colleges Credit hrs.: (2+1) King Saud University College of Science, Chemistry Department CHEM 109 CHAPTER 6: Carbohydrates Carbohydrates

More information

Vast majority of over 20 million known compounds are based on C: Generally contain C and H + other elements Great variety of compounds

Vast majority of over 20 million known compounds are based on C: Generally contain C and H + other elements Great variety of compounds 1 Vast majority of over 20 million known compounds are based on C: Generally contain C and + other elements Great variety of compounds 2 3 Isomers have identical composition but different structures Two

More information

Chemistry 2030 Introduction to Organic Chemistry Fall Semester 2012 Dr. Rainer Glaser

Chemistry 2030 Introduction to Organic Chemistry Fall Semester 2012 Dr. Rainer Glaser Chemistry 2030 Introduction to Organic Chemistry Fall Semester 2012 Dr. Rainer Glaser Examination #5: The Final Lipids, Carbohydrates, Nucleobases & DNA. Monday, December 10, 2012, 3 5 pm. Name: Question

More information

Final Exam, Page 1 of 15. Your full signature

Final Exam, Page 1 of 15. Your full signature Final Exam, Page 1 of 15 Your full signature Print your full name Your SID If you are making up an I grade Indicate the semester you took the course Name of the instructor for that course: This exam has

More information

Carbon s unique bonding pattern arises from the hybridization of the electrons.

Carbon s unique bonding pattern arises from the hybridization of the electrons. Unit 8 Neptune, the 8 th planet of our solar system Organic Chemistry Organic: compound containing carbon, excluding oxides and carbonates Carbon is an allotrope, meaning it has different bonding patterns.

More information

Functional Group. Chapter 7 Structure and Synthesis of Alkenes. Bond Lengths and Angles. Orbital Description. Pi Bond. Elements of Unsaturation

Functional Group. Chapter 7 Structure and Synthesis of Alkenes. Bond Lengths and Angles. Orbital Description. Pi Bond. Elements of Unsaturation Organic hemistry, 5 th Edition L. G. Wade, Jr. hapter 7 Structure and Synthesis of Alkenes Jo Blackburn Richland ollege, Dallas, TX Dallas ounty ommunity ollege District 2003, Prentice all Functional Group

More information

Properties of Alcohols and Phenols Experiment #3

Properties of Alcohols and Phenols Experiment #3 Properties of Alcohols and Phenols Experiment #3 Objectives: To observe the solubility of alcohols relative to their chemical structure, to perform chemical tests to distinguish primary, secondary and

More information

3/14/2011. Worked Example Stability of Alkenes. 7.4 Alkene Stereochemistry and the E,Z Designation

3/14/2011. Worked Example Stability of Alkenes. 7.4 Alkene Stereochemistry and the E,Z Designation 7.4 Alkene Stereochemistry and the E,Z Designation E,Z system Sequence rules used to assign priorities to the substituent groups on the double-bond carbons (alkenes) E double bond For German entgegen meaning

More information

Carbon and the Molecular Diversity of Life. Chapter 4

Carbon and the Molecular Diversity of Life. Chapter 4 Carbon and the Molecular Diversity of Life Chapter 4 CARBON Carbon is has ability to form large and complex, molecules Aspirin molecular formula? A triglyceride Organic chemistry is study of carbon compounds

More information

Model 2: Aldohexoses, aldopentoses, ketohexoses and ketopentoses

Model 2: Aldohexoses, aldopentoses, ketohexoses and ketopentoses Model 1: D and L Sugars CHEM1405 Worksheet 13: Sugars and Amino Acids The simplest sugar is glyceraldehyde. This is a chiral molecule and the two enantiomers are shown opposite with wedges and dashes and

More information

Charles S. McEnally* and Lisa D. Pfefferle. Department of Chemical Engineering and Center for Combustion Studies, Yale University, New Haven

Charles S. McEnally* and Lisa D. Pfefferle. Department of Chemical Engineering and Center for Combustion Studies, Yale University, New Haven Supporting Information for Sooting tendencies of oxygenated hydrocarbons in laboratory-scale flames Charles S. McEnally* and Lisa D. Pfefferle Department of Chemical Engineering and Center for Combustion

More information

Part I => CARBS and LIPIDS. 1.2 Monosaccharides 1.2a Stereochemistry 1.2b Derivatives

Part I => CARBS and LIPIDS. 1.2 Monosaccharides 1.2a Stereochemistry 1.2b Derivatives Part I => CARBS and LIPIDS 1.2 Monosaccharides 1.2a Stereochemistry 1.2b Derivatives Section 1.2a: Stereochemistry Synopsis 1.2a monosaccharide (greek) sugar - Monosaccharides are carbonyl polyols (or

More information

Lecture 3: 8/24. CHAPTER 3 Amino Acids

Lecture 3: 8/24. CHAPTER 3 Amino Acids Lecture 3: 8/24 CHAPTER 3 Amino Acids 1 Chapter 3 Outline 2 Amino Acid Are Biomolecules and their Atoms Can Be Visualized by Two Different Ways 1) Fischer projections: Two dimensional representation of

More information

Sheet #10 Dr. Mamoun Ahram Sec 1,2,3 15/07/2014. Carbohydrates 2

Sheet #10 Dr. Mamoun Ahram Sec 1,2,3 15/07/2014. Carbohydrates 2 Carbohydrates 2 A study Guide: Kindly,refer to the slide number,look at the structures and read the sheet notes well,most of the slides content besides all what the doctor said are mentioned here,good

More information

Practice Problems 3. a. What is the name of the bond formed between two amino acids? Are these bonds free to rotate?

Practice Problems 3. a. What is the name of the bond formed between two amino acids? Are these bonds free to rotate? Life Sciences 1a Practice Problems 3 1. Draw the oligopeptide for Ala-Phe-Gly-Thr-Asp. You do not need to indicate the stereochemistry of the sidechains. Denote with arrows the bonds formed between the

More information

CHAPTER 27 CARBOHYDRATES SOLUTIONS TO REVIEW QUESTIONS

CHAPTER 27 CARBOHYDRATES SOLUTIONS TO REVIEW QUESTIONS 27 09/17/2013 11:12:35 Page 397 APTER 27 ARBYDRATES SLUTINS T REVIEW QUESTINS 1. In general, the carbohydrate carbon oxidation state determines the carbon s metabolic energy content. The more oxidized

More information

CH [2] (ii) Give the structural formula of another hydrocarbon which is isomeric with the above.

CH [2] (ii) Give the structural formula of another hydrocarbon which is isomeric with the above. 1 The alkenes are unsaturated hydrocarbons. They form a homologous series, the members of which have the same chemical properties. They undergo addition reactions and are easily oxidised. (a) The following

More information

where R doesn t have to equal R or R

where R doesn t have to equal R or R hem 263 Nov 24, 2016 arboxylic Acids and Derivatives arboxylic acids are very important compounds in nature and serve as building blocks for preparing related derivatives such as esters and amides. The

More information

Carbohydrates 1. Steven E. Massey, Ph.D. Assistant Professor Bioinformatics Department of Biology University of Puerto Rico Río Piedras

Carbohydrates 1. Steven E. Massey, Ph.D. Assistant Professor Bioinformatics Department of Biology University of Puerto Rico Río Piedras Carbohydrates 1 Steven E. Massey, Ph.D. Assistant Professor Bioinformatics Department of Biology University of Puerto Rico Río Piedras Office & Lab: NCN#343B Tel: 787-764-0000 ext. 7798 E-mail: stevenemassey@gmail.com

More information

Chem 60 Takehome Test 2 Student Section

Chem 60 Takehome Test 2 Student Section Multiple choice: 1 point each. Mark only one answer for each question. 1. are composed primarily of carbon and hydrogen, but may also include oxygen, nitrogen, sulfur, phosphorus, and a few other elements.

More information

Carbohydrates CHAPTER SUMMARY

Carbohydrates CHAPTER SUMMARY 14 2 cellulose 2 2 arbohydrates 2 amylose APTER SUMMARY 14.1 hemical Nature of arbohydrates - Polyhydroxy Aldehydes and Ketones arbohydrates are a class of organic biopolymers which consist of polyhydroxy

More information

Chemistry 2050 Introduction to Organic Chemistry Fall Semester 2011 Dr. Rainer Glaser

Chemistry 2050 Introduction to Organic Chemistry Fall Semester 2011 Dr. Rainer Glaser Chemistry2050 IntroductiontoOrganicChemistry FallSemester2011 Dr.RainerGlaser Examination #5: The Final Lipids, Carbohydrates, Nucleobases & DNA. Monday, December 12, 2011, 10 am 12 pm. Name: Answer Key

More information

Review. Knowledge/Understanding. FeBr 3 + I 2 + HI. polymerization biochemistry. monosaccharide starch. (a) CH 3 CH 2 CHCH CH 3 CH 2 CHCOH

Review. Knowledge/Understanding. FeBr 3 + I 2 + HI. polymerization biochemistry. monosaccharide starch. (a) CH 3 CH 2 CHCH CH 3 CH 2 CHCOH Review Reflecting on Chapter 2 Summarize this chapter in the format of your choice. ere are a few ideas to use as guidelines: Describe the different types of organic reactions, and give an example of each

More information

Naming Organic Halide Organic Halide: is a compound that contains one or more halogen atoms (F, Cl, Br, I) as part of its molecular structure.

Naming Organic Halide Organic Halide: is a compound that contains one or more halogen atoms (F, Cl, Br, I) as part of its molecular structure. Naming Organic Halide Organic Halide: is a compound that contains one or more halogen atoms (F, Cl, Br, I) as part of its molecular structure. Organic halides have many important uses including: fire retardation,

More information

Dr. Nafith Abu Tarboush. Tarek Khrisat

Dr. Nafith Abu Tarboush. Tarek Khrisat 1 Dr. Nafith Abu Tarboush June 18 th 2013 Tarek Khrisat 1 Lecture Outline: Aldoses and Ketoses Optical isomers -Fischer projection -Enantiomers, Diastereomers, and Epimers Isomers: Compounds with the same

More information

C. Correct! A compound that consists only of hydrogen and carbon is termed a hydrocarbon.

C. Correct! A compound that consists only of hydrogen and carbon is termed a hydrocarbon. Organic Chemistry - Problem Drill 06: Alkanes and Cycloalkanes No. 1 of 10 1. What is a hydrocarbon? (A) A compound that consists of only carbon. (B) A compound that consists of nonmetals. (C) A compound

More information

9/6/2011. Amino Acids. C α. Nonpolar, aliphatic R groups

9/6/2011. Amino Acids. C α. Nonpolar, aliphatic R groups Amino Acids Side chains (R groups) vary in: size shape charge hydrogen-bonding capacity hydrophobic character chemical reactivity C α Nonpolar, aliphatic R groups Glycine (Gly, G) Alanine (Ala, A) Valine

More information

Chemistry 1050 Exam 3 Study Guide

Chemistry 1050 Exam 3 Study Guide Chapter 12 Chemistry 1050 Exam 3 Study Guide 12.1 a) Identify alkenes, alkynes and aromatics as unsaturated hydrocarbons. Determine the number of hydrogen atoms needed to complete an alkene structure.

More information

Chapter 7- Alkenes: Structure and Reactivity. Ashley Piekarski, Ph.D. Alkene

Chapter 7- Alkenes: Structure and Reactivity. Ashley Piekarski, Ph.D. Alkene Chapter 7- Alkenes: Structure and Reactivity Ashley Piekarski, Ph.D. Alkene What is an alkene func

More information

cyclobutane Benzene Ring phenyl

cyclobutane Benzene Ring phenyl ow many carbons and hydrogens in the following? More rganic Today eview hydrocarbons Functional Groups Condensation eaction Biopolymers A. 6 C, 14 B. 6 C, 15 C. 6 C, 16 3 1 2 D. 7 C, 15 3 1 1 3 E. 7 C,

More information

Stereoisomerism There are two types of stereoisomerism, E-Z Isomerism and Optical Isomerism.

Stereoisomerism There are two types of stereoisomerism, E-Z Isomerism and Optical Isomerism. Stereoisomerism There are two types of stereoisomerism, E-Z Isomerism and Optical Isomerism. E Z Isomerism This type tells us about the positions of substituent's either side of the carbon carbon double

More information

Supplement of Evaluation of NO + reagent ion chemistry for online measurements of atmospheric volatile organic compounds

Supplement of Evaluation of NO + reagent ion chemistry for online measurements of atmospheric volatile organic compounds Supplement of Atmos. Meas. Tech., 9, 2909 2925, 2016 http://www.atmos-meas-tech.net/9/2909/2016/ doi:10.5194/amt-9-2909-2016-supplement Author(s) 2016. CC Attribution 3.0 License. Supplement of Evaluation

More information

Organic_Chemistry_Presentation_v_1.0.notebook. June 02, Organic Chemistry. Organic Chemistry. Organic Chemistry

Organic_Chemistry_Presentation_v_1.0.notebook. June 02, Organic Chemistry. Organic Chemistry. Organic Chemistry Organic_hemistry_Presentation_v_1.0.notebook Organic hemistry Organic hemistry arbon and the Molecular iversity of Life arbon is the backbone of biological molecule Organic chemistry is the chemistry of

More information

بسم هللا الرحمن الرحيم

بسم هللا الرحمن الرحيم بسم هللا الرحمن الرحيم Biochemistry Lec #1 Dr. Nafith AbuTarboush- (30.6.2014) Amino Acids 1 Campbell and Farrell s Biochemistry, Chapter 3 (pp.66-76) Introduction: Biochemistry is two courses; one is

More information

(65 pts.) 27. (10 pts.) 28. (15 pts.) 29. (10 pts.) TOTAL (100 points) Moorpark College Chemistry 11 Spring Instructor: Professor Gopal

(65 pts.) 27. (10 pts.) 28. (15 pts.) 29. (10 pts.) TOTAL (100 points) Moorpark College Chemistry 11 Spring Instructor: Professor Gopal Moorpark College Chemistry 11 Spring 2012 Instructor: Professor Gopal Examination # 5: Section Five May 1, 2012 Name: (print) GOOD LUCK! Directions: Make sure your examination contains TWELVE total pages

More information