Organic Chemistry 3540

Similar documents
Organic Chemistry 3540

INTRODUCTION TO BIOCHEMISTRY/POLYMERS. 3. With respect to amino acids, polypeptides, and proteins, know:

2. Which of the following is NOT true about carbohydrates

Short polymer. Dehydration removes a water molecule, forming a new bond. Longer polymer (a) Dehydration reaction in the synthesis of a polymer

Moorpark College Chemistry 11 Fall Instructor: Professor Gopal. Examination # 5: Section Five May 7, Name: (print)

3150:112 SAMPLE TEST 2. Print out a copy Answer the questions on your own. Check the answers at GOBC Ans.pdf. Good Luck!

For more info visit

Model 2: Aldohexoses, aldopentoses, ketohexoses and ketopentoses

(30 pts.) 16. (24 pts.) 17. (20 pts.) 18. (16 pts.) 19. (5 pts.) 20. (5 pts.) TOTAL (100 points)

1. Denaturation changes which of the following protein structure(s)?

Moorpark College Chemistry 11 Fall Instructor: Professor Gopal. Examination #5: Section Five December 7, Name: (print) Section:

(65 pts.) 27. (10 pts.) 28. (15 pts.) 29. (10 pts.) TOTAL (100 points) Moorpark College Chemistry 11 Spring Instructor: Professor Gopal

The Structure and Function of Macromolecules

24.1 Introduction to Carbohydrates

AA s are the building blocks of proteins

Chemistry 107 Exam 3 Study Guide

3. AMINO ACID AND PEPTIDES

For questions 1-4, match the carbohydrate with its size/functional group name:

1. (38 pts.) 2. (25 pts.) 3. (15 pts.) 4. (12 pts.) 5. (10 pts.) Bonus (12 pts.) TOTAL (100 points)

Water: 1. The bond between water molecules is a(n) a. ionic bond b. covalent bond c. polar covalent bond d. hydrogen bond

For questions 1-4, match the carbohydrate with its size/functional group name:

Basic Biochemistry. Classes of Biomolecules

Downloaded from

Objective: You will be able to explain how the subcomponents of

Downloaded from

For questions 1-4, match the carbohydrate with its size/functional group name:

Biology 12 - Biochemistry Practice Exam

Macromolecules Structure and Function

Four Classes of Biological Macromolecules. Biological Macromolecules. Lipids

Biological systems interact, and these systems and their interactions possess complex properties. STOP at enduring understanding 4A

Biology 5A Fall 2010 Macromolecules Chapter 5

CHAPTER 23. Carbohydrates

Chapter 23 Carbohydrates and Nucleic Acids. Carbohydrates

Questions- Carbohydrates. A. The following structure is D-sorbose. (Questions 1 7) CH 2 OH C = O H C OH HO C H H C OH

CHAPTER 27 CARBOHYDRATES SOLUTIONS TO REVIEW QUESTIONS

I. Carbohydrates Overview A. Carbohydrates are a class of biomolecules which have a variety of functions. 1. energy

Long time ago, people who sacrifice their sleep, family, food, laughter, and other joys of life were called SAINTS. But now, they are called STUDENTS!

Most life processes are a series of chemical reactions influenced by environmental and genetic factors.

CHEM J-8 June 2014

1. Which of the following contributes to the tertiary structure of proteins?

Chapter 20 Carbohydrates Chapter 20

Chapter 20 and GHW#10 Questions. Proteins

Carbohydrates. Chapter 12

Biological Molecules

INTRODUCTION TO ORGANIC COMPOUNDS. Copyright 2009 Pearson Education, Inc.

The Chemical Building Blocks of Life. Chapter 3

CARBOHYDRATES (SUGARS)

Chapter Organic Chemistry. Functional Groups. Chapter The study of the compounds of carbon, not classified as inorganic.

Chapter 18. Carbohydrates with an Introduction to Biochemistry. Carbohydrates with an Introduction to Biochemistry page 1

Gentilucci, Amino Acids, Peptides, and Proteins. Peptides and proteins are polymers of amino acids linked together by amide bonds CH 3

Understand how protein is formed by amino acids

Chemistry 121 Winter 17

KEY NAME (printed very legibly) UT-EID

Molecular Biology. general transfer: occurs normally in cells. special transfer: occurs only in the laboratory in specific conditions.

Chapter 5: Structure and Function of Macromolecules AP Biology 2011

What are the molecules of life?

Biological Chemistry. Is biochemistry fun? - Find it out!

Organic molecules are molecules that contain carbon and hydrogen.

CHAPTER 21: Amino Acids, Proteins, & Enzymes. General, Organic, & Biological Chemistry Janice Gorzynski Smith

Acid/Base chemistry. NESA Biochemistry Fall 2001 Review problems for the first exam. Complete the following sentences

WHY IS THIS IMPORTANT?

Assignment #1: Biological Molecules & the Chemistry of Life

Macro molecule = is all the reactions that take place in cells, the sum of all chemical reactions that occur within a living organism Anabolism:

Chemistry 1120 Exam 2 Study Guide

Lesson 2. Biological Molecules. Introduction to Life Processes - SCI 102 1

Human Biochemistry Option B

Chp 2 (cont.) Organic Molecules. Spider s web and close up of capture strand - spider silk protein

1 C 2 C 3 C 4 C 5 C 6 C 7 C 8 C

Fundamentals of Organic Chemistry CHEM 109 For Students of Health Colleges

Macromolecules of Life -3 Amino Acids & Proteins

Organic Chemistry Diversity of Carbon Compounds

BIOMOLECULES & SPECTROSCOPY TABLE OF CONTENTS S.NO. TOPIC PAGE NO. i) Carbohydrates B3. ii) Proteins & Nucleic Acids.

Review of Biochemistry

3. Hydrogen bonds form between which atoms? Between an electropositive hydrogen and an electronegative N, O or F.

Chapter 5: The Structure and Function of Large Biological Molecules

3.1 Carbon is Central to the Living World

Third Exam Practice Test

Ionization of amino acids

Can you explain that monomers are smaller units from which larger molecules are made?

9/16/15. Properties of Water. Benefits of Water. More properties of water

Chemistry 1050 Exam 3 Study Guide

Unit 3: Chemistry of Life Mr. Nagel Meade High School

Additional problems: 1. Match and label the conjugate acid and base pairs in the following reactions. Which one of these systems is a good buffer?

Raghad Abu Jebbeh. Amani Nofal. Mamoon Ahram

AP BIOLOGY: READING ASSIGNMENT FOR CHAPTER 5

BIO 311C Spring Lecture 15 Friday 26 Feb. 1

Copyright 2008 Pearson Education, Inc., publishing as Pearson Benjamin Cummings

Chapter 3 Guided Reading Notes Carbon and the Molecular Diversity of Life

Slide 1. Slide 2. Slide 3. So far... All living things are primarily made up of four classes of Macromolecules

The Structure and Function of Large Biological Molecules

The Structure and Function of Large Biological Molecules Part 4: Proteins Chapter 5

ORGANIC AND BIOORGANIC CHEMISTRY

Study Guide Chapter 5 MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question

Carbohydrates are a large group of organic compounds occurring in and including,, and. They contain hydrogen and oxygen in the same ratio as (2:1).

2. Which of the following amino acids is most likely to be found on the outer surface of a properly folded protein?

The Structure and Function of Large Biological Molecules

Organic Chemistry III

Chapter 22 Carbohydrates

BCH 4053 Spring 2001 Chapter 7 Lecture Notes

Transcription:

rganic Chemistry 3540 December 8, 2004 (8 Pages, 13 Parts) ame 1. (8%) Many organic compounds found in living systems are complex molecules which can be characterized, in part, by simply listing the chemical class or the specific products of the complete hydrolysis of the complex molecule. Such products might include:. amino acids;. deoxyribose; C. glucose; D. glycerol; E. long chain saturated acids; F. long chain unsaturated acids; G. nitrogen bases;. phosphate ion; and I. ribose.. Some products J. might not be in the previous list. dditionally, some organic compounds found in living systems are complex molecules but which cannot be hydrolyzed at all L. ydrolysis involves the breaking of specific bond types which might include: M. acetal;. amide;. anhydride; P. ester; and R. hemiacetal.. Some bonds S might not be in this list. nd, compounds which are not hydrolyzed as bond type T.."Characterize" the following groups of naturally occurring molecules by placing in front of the compound the appropriate letter (or letters) above of the product(s) of complete hydrolysis of the naturally occurring molecule..give the bonding which is broken during such hydrolysis by placing after the compound the appropriate letter (or letters) of the bond(s) broken during complete hydrolysis. a. b. c. d. alkaloid cellulose starch simple protein 2. (10%) ptically active aldopentose was strongly oxidized with nitric acid to give optically inactive diacid. Degradation of gave optically active aldotetrose C. Degradation of C gave D-glyceraldehyde. itric acid oxidation of C gave optically active diacid D. Give Fischer projections of,, C, and D.

3. (4%) Each amino acid has its own unique isoelectric point, the p at which it is essentially electrically neutral. Four amino acids and their isoelectric points are shown below (The structures, of course, are not shown in the zwitterionic forms.). C C 2 C 2 C C 3 C S C 2 C 2 C C Glu = 3.22 2 Met = 5.74 2 3 C C C 2 (C 2 ) 4 C C 2 la = 6.01 Lys = 9.74 2 mino acids can separated by electrophoresis. Give the amino acid or acids of these four which: a. migrates towards the negative electrode in electrophoresis at p = 5.74. b. migrates towards the positive electrode in electrophoresis at p = 5.74. c. does not migrate towards the either electrode in electrophoresis at p = 5.74. 4. (7%) Draw the two dimensional structure of the tetrapeptide, Met-Glu-Lys-la. 5. (10%) In a study of rat liver aldehyde oxidase, a decapeptide was involved. Give the basic structure of the decapeptide based on the following analytical data. Edman degradation gave Gly. Carboxypeptidase analysis gave Val. Complete hydrolysis: sn =1; Gly = 1; Ile = 1; Pro = 2; Ser = 1; Trp = 1, Tyr = 1; Val = 2. Partial acid hydrolysis gave a complex mixture from which only two tripeptides were isolated in high enough yield and purity to be sequenced. They are: sn-ile-pro Ser-Tyr-Val Chymotrypsin hydrolysis (to the right of Phe, Tyr, and Trp) gave three small peptides with the following composition: sn, Ile, Pro, Val Gly, Ser, Tyr Pro, Val, Trp

6. (8%) Give simple chemical tests which will distinguish between the following. Give the formulas of reagents you would DD and tell what you would SEE. a. 2 b. 2 C 3 2 c. d. C 3 7. (4%) For each of the following examples, state if the example is an example of the primary, secondary, tertiary, or quaternary structure of the protein: a. folding of the helix in a globular protein b. association of four globins and four hemes in hemoglobin c. the amino acid sequence d. shape of a portion of the backbone, i.e., α-helix

8. (10%) Synthesize the following two compounds starting from benzene and compounds containing no more than two carbon atoms. a. b. I 9. (6%) The reaction of furan with bromine goes under milder conditions than benzene. Like benzene, it does not give addition product T. Like benzene, it gives a substitution product and it gives isomer V and not Z. 2, 0 o a. Is the resonance energy of furan greater than or less than benzene? T b. Explain, using appropriate structural drawings, why V is formed in preference to Z. V Z

10. (7%) Compound (C 7 17 ) is insoluble in 5% a but is soluble in 5% Cl. has 5 peaks in its C-13 MR spectrum. To determine the structure of, was treated with nitrous acid. Two fractions, and C (C 7 14 ) were collected by preparative gas chromatography. oth and C decolorized a solution of bromine in carbon tetrachloride. Detailed examination of revealed that it was a mixture of two cis-trans stereoisomers. Each stereoisomer of had 5 peaks in their C-13 MR spectra and C had 6 peaks. Treatment of with hot, acidic permanganate gave D (C 2 4 2 ) and E (C 5 10 2 ). D had two peaks in its C-13 MR spectrum and E had three peaks in its C-13 MR spectrum. Treatment of C with hot, acidic permanganate gave F (C 3 6 ) and G (C 4 8 ). F had two peaks in its C-13 MR spectrum and G had four peaks in its C-13 MR spectrum. oth F and G gave an orange-red precipitate with 2,4-DP. was treated with an excess of methyl iodide to give a salt, (C 10 24 I). was treated with silver oxide to give I (C 10 25 ), a compound as basic as a. eating I gave only and no C. a. Determine the structures of,, C, D, E, F, G,, and I. b. Suggest a reason why the nitrous acid treatment of gave two products while the heating of I gave only one product.

11. (12%) In each of the following, give the letter of the correct answer: a. Stronger base: b. Stronger base: 2 2 c. Stronger base: 2 2 3 C 2 d. Product: 2, 300 o C e. bsorbs UV-Visible photon of a lower energy: C 3 3 C C 3 3 C C C 2 C f. D-glyceraldehyde: C C C 2 C C 2 C 2 C g. Edman degradation of a polypeptide reveals:. The amino end ( terminus) of the peptide.. The carboxyl end (C terminus) of the peptide. C. The amino acid to the right of Phe, phenylalanine.

C 3 M C 2 C 2 C C 2 C 2 h. For the reaction of M,, and with enedict s reagent:. nly M gives a positive test.. nly gives a positive test. C. nly gives a positive test. D. nly M and give a positive test. E. nly M and give a positive test. F. nly and give a positive test. G. ll three give a positive test. i. hexose: C 2 C 2 j. The β-pleated sheet is most significantly associated with which structure of a protein?. Primary structure. Secondary structure C. Tertiary structure D. Quaternary structure k. n aldose: C 2 C 2 l. pyranose C 2 C 2

12. (5%) There are various bonds and attractions which are responsible for the unique conformation of an enzyme. List five of these bonds and attractions. 13. (9%) For each of the following, give the letter of only one compound which contains the structural feature requested. ote that some compounds contain more than one structural feature. a. acetal b. -acetal c. amide d. hemiacetal e. deoxy sugar f. pyranose g. furanose h. aldose i. ketose j. aldopentose E C 2 G I C 2 C 2 C 3 C 3 F J 3 C C 2 S 2 C 2 k. l. ketohexose undergoes mutarotation K. Structure ot Given bove m. nonreducing sugar