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BM 463 Your Name: Biochemistry and Physiology ID #: Final Exam, December 18, 2002 Prof. Jason Kahn You have 115 minutes for this exam. It is worth 250 points, so you are getting more points per minute than on the hour exams. You may use a calculator for this exam. No other study aids or materials are permitted. Generous partial credit will be given, i.e., if you don t know, guess. Explanations should be concise and clear. onor Pledge: Please write out the following sentence and sign it, or talk to me about it: I pledge on my honor that I have not given or received any unauthorized assistance on this examination. Possibly useful information: RT = 2476 J/mole today DG = DG + RTlnQ, where Q has the form of an equilibrium constant DG = -nfde, where F = 96500 J/(V mole), n = number of electrons transferred DG = -30.5 kj/mole for ATP 4- + 2 ADP 3- + P 2-4 + + De = 1.15V for NAD + 1/2 2 + + NAD + + 2 Michaelis-Menten equation: v 0 = V max [S]/(K M + [S]) Type of inhibition Apparent K M Apparent V max Apparent V max /K M ompetitive ak M V max (1/a) V max /K M Uncompetitive (1/a )K M (1/a ) V max V max /K M Mixed (a/a )K M (1/a ) V max (1/a) V max /K M Noncompetitive (a=a ) K M (1/a ) V max (1/a) V max /K M a = 1 + ([I]/K I ) a = 1 + ([I]/K I ) V max = k cat [E] total The Two Towers opens tonight. RELAX! READ TE QUESTIN, TEN ANSWER!

Biochemistry 463 Final Exam, 12/18/02 2 / 9 1. (16 pts) Name the pathway whose first step is catalyzed by glucose-6-phosphate dehydrogenase, G6PD. What is its main function in the red blood cell? Why have deleterious mutations in G6PD arisen and been maintained in some human populations? 2. (16 pts) Most fatty acids cannot support the net synthesis of glucose (in our cells) whereas most amino acids can. Explain why in terms of the TA cycle. Draw the structure of oxaloacetate.

Biochemistry 463 Final Exam, 12/18/02 3 / 9 3. (12 pts) We have made the analogy that fat is like gasoline, an efficient means of storing chemical energy. Give two fundamental reasons that fat stores energy more densely than glucose, both on an ATP per carbon basis and a kj/cm 3 basis. Following the analogy, if fat is gasoline then what is glucose? 4. (15 pts) Draw the structure of a ys-lys dipeptide at p 7. 5. (15 pts) Diabetes is a disease of cellular starvation in the midst of plenty. What is the difference between Type I and Type II diabetes? Briefly describe one metabolic consequence of nonresponsiveness to insulin (for example, decreased glucose transport into cells but pick another one), and one disease symptom arising from the presence of excess glucose in the blood or other tissues.

Biochemistry 463 Final Exam, 12/18/02 4 / 9 6. (12 pts) For the reactions below, name the enzyme that catalyzes the reaction and add the other necessary reactants and products (things like ATP, ADP, 2, etc) on the lines given. Don t worry about water or protons. 2-2 - - - - Enzyme: - - P Enzyme: 7. (12 pts) It is often observed that enzymes that catalyze near-equilibrium reactions in a given pathway are present in much larger amounts than those that catalyze strongly exergonic steps. Why might this be necessary in terms of maintaining flux? Why are the enzymes of anaerobic glycolysis present in larger quantities than TA cycle enzymes in skeletal muscle?

Biochemistry 463 Final Exam, 12/18/02 5 / 9 8. (16 pts) Why are acetyl phosphate and Acetyl-oA (shown below) each high-energy molecules (two separate explanations with a common thread)? Draw the products of (thio)ester hydrolysis for each. P S oa 2 2 9. (13 pts) Briefly speculate on the metabolic consequences of a hemoglobin mutant with reduced oxygen-binding cooperativity (a lower ill coefficient than normal) but a normal p50. What might one cellular response to hypoxia be? [These are important in solid tumors, which often are relatively anaerobic.]

Biochemistry 463 Final Exam, 12/18/02 6 / 9 10. (12 pts) Draw the next two steps in the binding change mechanism for ATP synthesis in oxidative phosphorylation: 11. (16 pts) Briefly describe the key steps of the phosphorylation cascade that activates glycogen breakdown in response to glucagon.

Biochemistry 463 Final Exam, 12/18/02 7 / 9 12. (20 pts) ne intermediate in the lass I aldolase reaction is shown below. Draw the arrow pushing and the next structure (going toward GAP + DAP) in the reaction mechanism. Draw the DAP product of the reaction. What kinds of catalysis are illustrated by this mechanism? 2 P 3 2- N ( 2 ) 4 Enz B 2 P 3 2-13. (25 pts) Name the electron donors and acceptors for electron transport by omplexes I, II, III, and IV (just initial and final for each one). Why does FAD 2 oxidation provide less ATP than NAD reduction?

Biochemistry 463 Final Exam, 12/18/02 8 / 9 14. (12 pts) It is occasionally observed that an enzyme with a mutation of a serine to glutamate acts as if it were always phosphorylated at the serine. Draw the phosphoserine and glutamate side chains, and speculate on the structural origin of the functional change. 15. (20 pts) Use the following sequence for this problem: Lys-Val-Glu-Glu-Leu-Leu-Ser-Lys-Asn-Tyr n the helical wheel representation to the right, enter the amino acid from the above sequence which would be at each position. The N-terminal Lysine is entered for you, and the helix runs from N-term to -term away from you, into the page. Does this a-helix have an amphipathic moment (i.e. one hydrophobic side and one hydrophilic side)? If it does, indicate which side is which on the helical wheel. ircle one: Yes No Which side of the helix is most likely to face the inside of the protein, and why? It is observed that phosphorylation at serine destabilizes the folding of this a-helix. Why might this be the case?

Biochemistry 463 Final Exam, 12/18/02 9 / 9 16. (18 points) Pure non-competitive inhibition, as we have discussed, is quite rare. owever, it is still a useful idea. Sketch the lines on the Lineweaver-Burk plot below corresponding to noncompetitive inhibition at increasing inhibitor concentrations. 100 Lineweaver-Burk Plot 80 1/v 0 60 40 20 0-0.4-0.2 0 0.2 0.4 0.6 0.8 1 1/[S] It turns out that irreversible inhibition of an enzyme at different reagent concentrations has the same kinetic signature as non-competitive inhibition. With reference to the definition of V max, explain why. Page 2: /32 Page 3: /42 Page 4: /24 Page 5: /29 Page 6: /28 Page 7: /45 Page 8: /32 Page 9: /18 TTAL /250