Finite Element Analysis of Radius and Ulna. Eli Pavlatos April 24, 2013

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Finite Element Analysis of Radius and Ulna Eli Pavlatos April 24, 2013

Outline Review bone biomechanics bone behavior during fracture Stress analysis concepts properties of bone for models Fracture simulations Analysis results Conclusion

Why Bones Break Key relationship: force applied to a structure and displacement S stiffness F u ultimate force U work to failure d u ultimate displacement

Why Bones Break Re-express force and displacement as stress and strain Stress 1 Pa 1 apple on square meter tabletop Strain ratio of lengths so unitless

Why Bones Break Similar to force-displacement curve E = intrinsic stiffness Strength is intrinsic property of bone Force required to break varies with bone size Post yield = permanent

Analysis Concepts Young s Modulus Shear Modulus Poisson s Ratio No density E = Young's modulus F n = force normal to faces A = area ε l = linear strain

Analysis Concepts Young s Modulus Shear Modulus Poisson s Ratio No density S = shear modulus F p = force parallel to faces A = area ε s = shear strain

Analysis Concepts Young s Modulus Shear Modulus Poisson s Ratio No density υ = Poisson's ratio ε t = transverse strain ε l = longitudinal or axial strain

Analysis Concepts Ultimate stress increases from transverse to longitudinal force Also dependent on tensile or compressive force

Analysis Concepts Bone property values Longitudinal Transverse Young's Modulus 17 GPa 11.5 GPa Shear Modulus 3.6 GPa 3.3 GPa Poisson's Ratio 0.6 0.3 Ultimate stresses: Longitudinal compression: 200 MPa Longitudinal tension: 140 MPa Transverse compression: 130 MPa

Radius Catching Fall Hold proximal end fixed Forces applied to underside of distal end Expected stresses: Compression on top near constraints Tension on opposite side

Radius Catching Fall

Radius Catching Fall Von Mises Stress: combines linear and shear stresses from all directions into one value Max compression: 180 MPa 200 MPa Max tension: 140 MPa 160 MPa Fracture from tension most likely Applied force of 1160 N

Ulna Catching Fall Max compression and tension: 140 MPa 156 MPa Tension only cause of fracture Applied force of 1610 N

Radius Middle Load Proximal and distal ends fixed Load applied at midpoint of bone Expected stresses: Compression/tension near constraints Transverse compression at midpoint

Radius Middle Load

Radius Middle Load Max compression: 130 MPa 145 MPa Max tension: 72 MPa 87 MPa Fracture near center due to compression Applied force of 4720 N

Ulna Middle Load Max compression: 125 MPa 140 MPa Max tension: 140 MPa 156 MPa Fracture near midpoint from compression Fracture from tension at wrist Applied force of 7450 N

Radius Compress Ends Proximal end fixed Rest of bone limited to motion along z-axis Expected stresses: compression throughout bone

Radius Compress Ends

Radius Compress Ends Max compression: 200 MPa 223 MPa No tension Fracture near center due to longitudinal compression Applied force of 34,200 N

Ulna Compress Ends Max compression: 200 MPa 223 MPa No tension Fracture more toward distal end than for radius Applied force of 40,200 N

Radius Twist Proximal end fixed as before Force Couple used to simulate twist Expected stresses Torsion around z-axis

Radius Twist

Radius Twist Ultimate stress = 49 68 MPa Max torsion: 45 MPa 68 MPa Fracture risk for much of bone Applied force of 3020 N Torque of 54.66 N m

Ulna Twist Use region with only torsion stress Max torsion: 45 MPa 68 MPa Fracture from torsion near middle Applied force of 4,400 N Torque of 78.59 N m

Summary of Forces Radius Ulna Catching Fall 1,160 N 1,610 N Mid 4,720 N 7,450 N Comp 34,200 N 40,200 N Stretch 23,895 N 28,100 N Twist 54.66 N m 78.59 N m

Conclusion Was able to find fracture locations in radius and ulna for different simulations Resulting forces agreed with accepted models of bone anisotropy Ulna required larger forces Due to bone size and shape possibly described by Wolff s Law bone in a healthy person or animal will adapt to the loads under which it is placed

Thank You Dr. Voytas Dr. George Dr. Williams

Sources http://www.melioguide.com/media/121650/turner_bone_strength.pdf http://medical-dictionary.thefreedictionary.com/wolff's+law http://www.colorado.edu/mcen/mcen4173/chap_01.pdf http://www.engineeringtoolbox.com/stress-strain-d_950.html http://www.engineeringtoolbox.com/poissons-ratio-d_1224.html http://www.teambone.com/biomechanics.html http://silver.neep.wisc.edu/~lakes/bme315n3.pdf http://silver.neep.wisc.edu/~lakes/boneaniso.html http://topex.ucsd.edu/geodynamics/shearer.pdf http://web.mit.edu/awinter/public/mgh%20literature/wirtz-2000- Evaluation%20of%20known%20bone%20material%20properties.pdf http://blog.design-point.com/blog/2013/january/solidworkssimulation-what-is-von-mises-stress-part-2-of-2.aspx#.uxc-nbesiso

Questions?

Radius Stretch Ends Same constraints used as in compression Direction of force flipped Expected stresses: Tension along entire bone

Radius Stretch Ends

Radius Stretch Ends No compression Max tension: 140 MPa 156 MPa Fracture due to longitudinal tension Similar to position of compression fracture Applied force of 23,895 N

Ulna Stretch Ends No compression Max tension: 140 MPa 156 MPa Fracture again closer to wrist Applied force of 28,100 N

Analysis Basics Stress Strain

Why Bones Break Biomechanical status of bone may be poorly described by just one of these properties Osteopetrotic patient stiff, but brittle Young child poorly mineralized and weak, but ductile

Why Bones Break Inverse relationship between Young s modulus and ultimate strain Antler: mineralization, strain, E

Why Bones Break For my project, using curve for typical bone strength Will be looking for ultimate strength value given by program

Current Model

Current Model

Future Work Want to find stresses necessary to cause fractures of arm bones Current issues: Thickness of the model Obtaining sensible units Creating realistic fracture scenarios

Future Work Want to consider the anisotropic nature of bone

Conclusion Bone fractures depend on multiple factors Want to find fracture point by examining maximum stress Next step is to get meaningful units and realistic fracture models Then want to consider anisotropic behavior

Works Cited http://www.melioguide.com/media/121650/turne r_bone_strength.pdf http://en.wikipedia.org/wiki/fracture http://www.brown.edu/departments/eeb/eml/ background/bone.htm

FEA Review FEA is numerical method which provides solutions to difficult problems stress analysis, fluid flow, heat transfer, etc. Math behind analysis relies heavily on use of matrices LISA and other programs allow complex computations to be carried out quickly Want to use LISA to perform static analysis on bone fractures

FEA Review Beam Example

Why Bones Break 1. Ultimate tensile strength 2. Yield strength 3. Proportional limit stress 4. Fracture 5. Offset strain (typically 0.2%)